we just finished electing a new Democratic and wholly progressive Senator (woohoo!) in Jeff Merkley, but it'll likely go Democratic too.
Right now, the Republican party in Oregon is moribund, with only one federal representative, and no statewide elected officials and significant minority status in both the House and Senate. So, they have a weak bench.
On the Democratic side, it's an embarrassment of riches, but from personal discussion with the former Democratic Governor, John Kitzhaber, he's angling to run again, in which case it's a blowout-- his approval ratings were in the 70% range!
As admiralnaismith said, you can focus on other states, Oregon is wrapped up.
sole Republican-held Congressional district of the 5 in Oregon, because Greg Walden is almost certainly going to run for Governor next time and it would have been helpful to have had someone make him actually spend some of his money instead of just being able to accumulate a warchest that he can then transfer.
If for nothing else, making the Republicans spend some of their money is reason enough to contest every seat.
determine whether Hillary's "victories" in Michigan and Florida count.
At this point, it looks like Obama has a lock on the pledged delegates, so hopefully that will settle the issue of FL and MI, and it will only come down to him winning enough superdelegates to hold her back.
My hope is that the superdelegates from all of the red and/or small states that Obama has been winning will fall in line behind him.
Starrett won't draw nearly as many from the Right as Frohnmeyer will from the Left.
Frohnmeyer is a Republican in name only, in fact not even that as he is an Independent, he will run on a platform that will likely be to the left of everyone else on several fronts--- who else has called for the impeachment of Bush?
I'm not supporting Frohnmeyer here, but the math is still difficult for Merkley/Novick as a certain segment of the population will not know about Frohnmeyer's (moderate) Republican roots, they will only hear his leftist platform.